n/7-(2n+5)=19

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Solution for n/7-(2n+5)=19 equation: 



n/7-(2n+5)=19

We move all terms to the left:

n/7-(2n+5)-(19)=0

We get rid of parentheses

n/7-2n-5-19=0

We multiply all the terms by the denominator


n-2n*7-5*7-19*7=0

We add all the numbers together, and all the variables

n-2n*7-168=0

Wy multiply elements

n-14n-168=0

We add all the numbers together, and all the variables

-13n-168=0

We move all terms containing n to the left, all other terms to the right

-13n=168

n=168/-13

n=-12+12/13

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