n/n-3+(4)=n/n-3

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Solution for n/n-3+(4)=n/n-3 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n/n-3+4 = n/n-3 // - n/n-3

n/n-(n/n)-3+3+4 = 0

n/n-3-1+3+4 = 0

4 = 0

n belongs to the empty set

n belongs to the empty set

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