If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( n )
n = 0
n = 0
n = 0
n in (-oo:0) U (0:+oo)
n/n-4 = (2*n)/n+4 // - (2*n)/n+4
n/n-((2*n)/n)-4-4 = 0
n/n-4-4-2 = 0
-9 = 0
n belongs to the empty set
n belongs to the empty set
| 550x+17615=74815 | | (3r-8)(7r+4)=0 | | 32x^2-18x=0 | | 5(3-c/7)=8+1+2/3c | | 75x^2-27=0 | | X+2/X+8=X-2/X+4 | | n+-8=25 | | 550x+17615= | | c/5-15=-8 | | x^2-62x+61=0 | | 13x+3=15x-7 | | (8+8i)+(10-7i)= | | 5x-5=25y | | x^3-6x^2-247x+1020=0 | | 35+4(x-3)=7x-12 | | (2a/5b)(3b/8) | | 31=4-9v | | (3y/y+3)+(9/y)+3=(27/y^2+3y) | | 2(v+2)=2v+20 | | -16x^2+350x+40=500 | | 5x+8=7x-8 | | 3(n+1)=n+19 | | 3(x)+4(y)=75000 | | X=2/5y | | 43x-4=77 | | 0.05x-1.82=0.708x-0.504 | | 1/3(6y-9)=13-2y | | 5(x+9)=2x+15 | | a/(-4)+14=20 | | 4(2y+1)-5=-10(y-5) | | 10(z+1)-3(z-3)=3(z-3)+3(z-3) | | 9x/8-x=x/40-2/5 |