n2+12n-23=0

Solution for n2+12n-23=0 equation:

n2+12n-23=0

We add all the numbers together, and all the variables

n^2+12n-23=0

a = 1; b = 12; c = -23;
Δ = b2-4ac
Δ = 122-4·1·(-23)
Δ = 236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{236}=\sqrt{4*59}=\sqrt{4}*\sqrt{59}=2\sqrt{59}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{59}}{2*1}=\frac{-12-2\sqrt{59}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{59}}{2*1}=\frac{-12+2\sqrt{59}}{2}
$