n2+1=-8n+(7n+n)

Solution for n2+1=-8n+(7n+n) equation:

n2+1=-8n+(7n+n)

We move all terms to the left:

n2+1-(-8n+(7n+n))=0

We add all the numbers together, and all the variables

n2-(-8n+(+8n))+1=0

We add all the numbers together, and all the variables

n^2-(-8n+(+8n))+1=0


We calculate terms in parentheses: -(-8n+(+8n)), so:

-8n+(+8n)

We get rid of parentheses

-8n+8n

We add all the numbers together, and all the variables



Back to the equation:

-()


We add all the numbers together, and all the variables

n^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{2}=0$