n2+201n-2700=0

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Solution for n2+201n-2700=0 equation:



n2+201n-2700=0
We add all the numbers together, and all the variables
n^2+201n-2700=0
a = 1; b = 201; c = -2700;
Δ = b2-4ac
Δ = 2012-4·1·(-2700)
Δ = 51201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{51201}=\sqrt{9*5689}=\sqrt{9}*\sqrt{5689}=3\sqrt{5689}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(201)-3\sqrt{5689}}{2*1}=\frac{-201-3\sqrt{5689}}{2} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(201)+3\sqrt{5689}}{2*1}=\frac{-201+3\sqrt{5689}}{2} $

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