n2+26n+169=0

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Solution for n2+26n+169=0 equation: 



n2+26n+169=0

We add all the numbers together, and all the variables

n^2+26n+169=0

a = 1; b = 26; c = +169;
Δ = b2-4ac
Δ = 262-4·1·169
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-26}{2}=-13$

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