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n2+4n-1440=0
We add all the numbers together, and all the variables
n^2+4n-1440=0
a = 1; b = 4; c = -1440;
Δ = b2-4ac
Δ = 42-4·1·(-1440)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-76}{2*1}=\frac{-80}{2} =-40 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+76}{2*1}=\frac{72}{2} =36 $
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