n2+n-2=60

Solution for n2+n-2=60 equation:

n2+n-2=60

We move all terms to the left:

n2+n-2-(60)=0

We add all the numbers together, and all the variables

n^2+n-62=0

a = 1; b = 1; c = -62;
Δ = b2-4ac
Δ = 12-4·1·(-62)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{249}}{2*1}=\frac{-1-\sqrt{249}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{249}}{2*1}=\frac{-1+\sqrt{249}}{2}
$