If it's not what You are looking for type in the equation solver your own equation and let us solve it.
n2-12n=0
We add all the numbers together, and all the variables
n^2-12n=0
a = 1; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·1·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*1}=\frac{0}{2} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*1}=\frac{24}{2} =12 $
| 4/5w-4/3=-1/2 | | X-3-7x=51 | | -7x+3+6x=-3 | | 1/5=-1/3u-1/4 | | 8g-2g=18 | | 6+6x+x=34 | | m^2-10m-36=0 | | (2x+87)/3=90 | | x+9+x+4x=105 | | 5(2-u))-u=2(u+1) | | w-5.11=9.9 | | -3+20=4x-22 | | -0.05z+0.9z=51= | | 10/9=-5w | | x/32.4=22 | | 0.8x+1=0.75x+0.7 | | 49=x/7 | | 6=78/v | | 2x2+10x2+12x=0 | | 21=-4(9x+8) | | 2x3+10x2+12x=0 | | w/3=w/2+4 | | 10(b-3)=-28 | | 160=b/4 | | 12(2-3b)=60 | | 11x^2-26x+15=0 | | 2(x+6)=6x-24 | | -30=-5(6b-6) | | -5(4+2v)=-17 | | (3x+20)+45=116 | | -20=-2(10-4b) | | 5x+1-2x=13 |