n2-16n+15=0

Solution for n2-16n+15=0 equation:

n2-16n+15=0

We add all the numbers together, and all the variables

n^2-16n+15=0

a = 1; b = -16; c = +15;
Δ = b2-4ac
Δ = -162-4·1·15
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-14}{2*1}=\frac{2}{2}
=1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+14}{2*1}=\frac{30}{2}
=15
$