n2-16n+63=(n-7)(n+)

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Solution for n2-16n+63=(n-7)(n+) equation: 



n2-16n+63=(n-7)(n+)

We move all terms to the left:

n2-16n+63-((n-7)(n+))=0

We add all the numbers together, and all the variables

n2-16n-((n-7)(+n))+63=0

We add all the numbers together, and all the variables

n^2-16n-((n-7)(+n))+63=0

We multiply parentheses ..

n^2-((+n^2-7n))-16n+63=0



We calculate terms in parentheses: -((+n^2-7n)), so:

(+n^2-7n)

We get rid of parentheses

n^2-7n

Back to the equation:

-(n^2-7n)



We add all the numbers together, and all the variables

n^2-16n-(n^2-7n)+63=0

We get rid of parentheses

n^2-n^2-16n+7n+63=0

We add all the numbers together, and all the variables

-9n+63=0

We move all terms containing n to the left, all other terms to the right

-9n=-63

n=-63/-9

n=+7

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