n2-3n-1000=0

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Solution for n2-3n-1000=0 equation:



n2-3n-1000=0
We add all the numbers together, and all the variables
n^2-3n-1000=0
a = 1; b = -3; c = -1000;
Δ = b2-4ac
Δ = -32-4·1·(-1000)
Δ = 4009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{4009}}{2*1}=\frac{3-\sqrt{4009}}{2} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{4009}}{2*1}=\frac{3+\sqrt{4009}}{2} $

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