n2=1.5

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Solution for n2=1.5 equation:



n2=1.5
We move all terms to the left:
n2-(1.5)=0
We add all the numbers together, and all the variables
n^2-1.5=0
a = 1; b = 0; c = -1.5;
Δ = b2-4ac
Δ = 02-4·1·(-1.5)
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6}}{2*1}=\frac{0-\sqrt{6}}{2} =-\frac{\sqrt{}}{2} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6}}{2*1}=\frac{0+\sqrt{6}}{2} =\frac{\sqrt{}}{2} $

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