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n2=180
We move all terms to the left:
n2-(180)=0
We add all the numbers together, and all the variables
n^2-180=0
a = 1; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·1·(-180)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*1}=\frac{0-12\sqrt{5}}{2} =-\frac{12\sqrt{5}}{2} =-6\sqrt{5} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*1}=\frac{0+12\sqrt{5}}{2} =\frac{12\sqrt{5}}{2} =6\sqrt{5} $
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