n2=3.5

Solution for n2=3.5 equation:

n2=3.5

We move all terms to the left:

n2-(3.5)=0

We add all the numbers together, and all the variables

n^2-3.5=0

a = 1; b = 0; c = -3.5;
Δ = b2-4ac
Δ = 02-4·1·(-3.5)
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{14}}{2*1}=\frac{0-\sqrt{14}}{2}
=-\frac{\sqrt{}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{14}}{2*1}=\frac{0+\sqrt{14}}{2}
=\frac{\sqrt{}}{2}
$