n3=n/3

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Solution for n3=n/3 equation: 


n in (-oo:+oo)

n^3 = n/3 // - n/3

n^3-(n/3) = 0

n^3-1/3*n = 0

n*(n^2-1/3) = 0

1*n^2 = 1/3 // : 1

n^2 = 1/3

n^2 = 1/3 // ^ 1/2

abs(n) = (1/3)^(1/2)

n = (1/3)^(1/2) or n = -(1/3)^(1/2)

n = 0

n = 0

n in { (1/3)^(1/2), -(1/3)^(1/2), 0 }

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