n=(n+3)2+2n-9

Solution for n=(n+3)2+2n-9 equation:

n=(n+3)2+2n-9

We move all terms to the left:

n-((n+3)2+2n-9)=0


We calculate terms in parentheses: -((n+3)2+2n-9), so:

(n+3)2+2n-9

We add all the numbers together, and all the variables

2n+(n+3)2-9

We multiply parentheses

2n+2n+6-9

We add all the numbers together, and all the variables

4n-3

Back to the equation:

-(4n-3)


We get rid of parentheses

n-4n+3=0

We add all the numbers together, and all the variables

-3n+3=0

We move all terms containing n to the left, all other terms to the right

-3n=-3

n=-3/-3

n=1