n=10(40-2n)

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Solution for n=10(40-2n) equation:



n=10(40-2n)
We move all terms to the left:
n-(10(40-2n))=0
We add all the numbers together, and all the variables
n-(10(-2n+40))=0
We calculate terms in parentheses: -(10(-2n+40)), so:
10(-2n+40)
We multiply parentheses
-20n+400
Back to the equation:
-(-20n+400)
We get rid of parentheses
n+20n-400=0
We add all the numbers together, and all the variables
21n-400=0
We move all terms containing n to the left, all other terms to the right
21n=400
n=400/21
n=19+1/21

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