n=2(s+2)+4(s+1)

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Solution for n=2(s+2)+4(s+1) equation:


Simplifying
n = 2(s + 2) + 4(s + 1)

Reorder the terms:
n = 2(2 + s) + 4(s + 1)
n = (2 * 2 + s * 2) + 4(s + 1)
n = (4 + 2s) + 4(s + 1)

Reorder the terms:
n = 4 + 2s + 4(1 + s)
n = 4 + 2s + (1 * 4 + s * 4)
n = 4 + 2s + (4 + 4s)

Reorder the terms:
n = 4 + 4 + 2s + 4s

Combine like terms: 4 + 4 = 8
n = 8 + 2s + 4s

Combine like terms: 2s + 4s = 6s
n = 8 + 6s

Solving
n = 8 + 6s

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Simplifying
n = 8 + 6s

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