n=2k+3(k-1)

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Solution for n=2k+3(k-1) equation: 



=2N+3(N-1)

We move all terms to the left:

-(2N+3(N-1))=0



We calculate terms in parentheses: -(2N+3(N-1)), so:

2N+3(N-1)

We multiply parentheses

2N+3N-3

We add all the numbers together, and all the variables

5N-3

Back to the equation:

-(5N-3)



We get rid of parentheses

-5N+3=0

We move all terms containing N to the left, all other terms to the right

-5N=-3

N=-3/-5

N=3/5

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