n=3(1+2n)=17

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Solution for n=3(1+2n)=17 equation: 



n=3(1+2n)=17

We move all terms to the left:

n-(3(1+2n))=0

We add all the numbers together, and all the variables

n-(3(2n+1))=0



We calculate terms in parentheses: -(3(2n+1)), so:

3(2n+1)

We multiply parentheses

6n+3

Back to the equation:

-(6n+3)



We get rid of parentheses

n-6n-3=0

We add all the numbers together, and all the variables

-5n-3=0

We move all terms containing n to the left, all other terms to the right

-5n=3

n=3/-5

n=-3/5

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