n=3+2(n-1)

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Solution for n=3+2(n-1) equation: 



n=3+2(n-1)

We move all terms to the left:

n-(3+2(n-1))=0



We calculate terms in parentheses: -(3+2(n-1)), so:

3+2(n-1)

determiningTheFunctionDomain
2(n-1)+3

We multiply parentheses

2n-2+3

We add all the numbers together, and all the variables

2n+1

Back to the equation:

-(2n+1)



We get rid of parentheses

n-2n-1=0

We add all the numbers together, and all the variables

-1n-1=0

We move all terms containing n to the left, all other terms to the right

-n=1

n=1/-1

n=-1

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