n=360n(2-n)

Solution for n=360n(2-n) equation:

n=360n(2-n)

We move all terms to the left:

n-(360n(2-n))=0

We add all the numbers together, and all the variables

n-(360n(-1n+2))=0


We calculate terms in parentheses: -(360n(-1n+2)), so:

360n(-1n+2)

We multiply parentheses

-360n^2+720n

Back to the equation:

-(-360n^2+720n)


We get rid of parentheses

360n^2-720n+n=0

We add all the numbers together, and all the variables

360n^2-719n=0

a = 360; b = -719; c = 0;
Δ = b2-4ac
Δ = -7192-4·360·0
Δ = 516961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{516961}=719$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-719)-719}{2*360}=\frac{0}{720}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-719)+719}{2*360}=\frac{1438}{720}
=1+359/360
$