n=4(2n+32)+2(n+9/2)

Solution for n=4(2n+32)+2(n+9/2) equation:

n=4(2n+32)+2(n+9/2)

We move all terms to the left:

n-(4(2n+32)+2(n+9/2))=0

We add all the numbers together, and all the variables

n-(4(2n+32)+2(+n+9/2))=0

We multiply all the terms by the denominator


n*2))-(4(2n+n+9+32)+2(=0

We add all the numbers together, and all the variables

n*2))-(4(3n+41)+2(=0

We add all the numbers together, and all the variables

n*2))-(4(3n=0

Wy multiply elements

2n^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{4}=0$