n=5+4(n-1)

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Solution for n=5+4(n-1) equation: 



n=5+4(n-1)

We move all terms to the left:

n-(5+4(n-1))=0



We calculate terms in parentheses: -(5+4(n-1)), so:

5+4(n-1)

determiningTheFunctionDomain
4(n-1)+5

We multiply parentheses

4n-4+5

We add all the numbers together, and all the variables

4n+1

Back to the equation:

-(4n+1)



We get rid of parentheses

n-4n-1=0

We add all the numbers together, and all the variables

-3n-1=0

We move all terms containing n to the left, all other terms to the right

-3n=1

n=1/-3

n=-1/3

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