n=n(3n+1)/2

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Solution for n=n(3n+1)/2 equation: 



n=n(3n+1)/2

We move all terms to the left:

n-(n(3n+1)/2)=0

We multiply all the terms by the denominator


n*2)-(n(3n+1)=0

Wy multiply elements

2n^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{4}=0$

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