n=n2-5n+2

Solution for n=n2-5n+2 equation:

n=n2-5n+2

We move all terms to the left:

n-(n2-5n+2)=0

We add all the numbers together, and all the variables

-(+n^2-5n+2)+n=0

We get rid of parentheses

-n^2+5n+n-2=0

We add all the numbers together, and all the variables

-1n^2+6n-2=0

a = -1; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·(-1)·(-2)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{7}}{2*-1}=\frac{-6-2\sqrt{7}}{-2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{7}}{2*-1}=\frac{-6+2\sqrt{7}}{-2}
$