p(1-p)=0,28

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Solution for p(1-p)=0,28 equation: 



p(1-p)=0.28

We move all terms to the left:

p(1-p)-(0.28)=0

We add all the numbers together, and all the variables

p(-1p+1)-(0.28)=0

We add all the numbers together, and all the variables

p(-1p+1)-0.28=0

We multiply parentheses

-1p^2+p-0.28=0

a = -1; b = 1; c = -0.28;
Δ = b2-4ac
Δ = 12-4·(-1)·(-0.28)
Δ = -0.12
Delta is less than zero, so there is no solution for the equation

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