p(6p-5)=0

Solution for p(6p-5)=0 equation:

p(6p-5)=0

We multiply parentheses

6p^2-5p=0

a = 6; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·6·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*6}=\frac{0}{12}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*6}=\frac{10}{12}
=5/6
$