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p(9+3)=p(12)
We move all terms to the left:
p(9+3)-(p(12))=0
determiningTheFunctionDomain p(9+3)-p12=0
We add all the numbers together, and all the variables
p12-p12=0
We add all the numbers together, and all the variables
=0
p=0/1
p=0
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