p(p-2)=45

Solution for p(p-2)=45 equation:

p(p-2)=45

We move all terms to the left:

p(p-2)-(45)=0

We multiply parentheses

p^2-2p-45=0

a = 1; b = -2; c = -45;
Δ = b2-4ac
Δ = -22-4·1·(-45)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{46}}{2*1}=\frac{2-2\sqrt{46}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{46}}{2*1}=\frac{2+2\sqrt{46}}{2}
$