p(p-3)2-4(p-3)3=0

Solution for p(p-3)2-4(p-3)3=0 equation:

p(p-3)2-4(p-3)3=0

We multiply parentheses

2p^2-6p-12p+36=0

We add all the numbers together, and all the variables

2p^2-18p+36=0

a = 2; b = -18; c = +36;
Δ = b2-4ac
Δ = -182-4·2·36
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6}{2*2}=\frac{12}{4}
=3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6}{2*2}=\frac{24}{4}
=6
$