p(p-q)+(d+p)=

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Solution for p(p-q)+(d+p)= equation:


Simplifying
p(p + -1q) + (d + p) = 0
(p * p + -1q * p) + (d + p) = 0

Reorder the terms:
(-1pq + p2) + (d + p) = 0
(-1pq + p2) + (d + p) = 0

Remove parenthesis around (d + p)
-1pq + p2 + d + p = 0

Reorder the terms:
d + p + -1pq + p2 = 0

Solving
d + p + -1pq + p2 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1p' to each side of the equation.
d + p + -1pq + -1p + p2 = 0 + -1p

Reorder the terms:
d + p + -1p + -1pq + p2 = 0 + -1p

Combine like terms: p + -1p = 0
d + 0 + -1pq + p2 = 0 + -1p
d + -1pq + p2 = 0 + -1p
Remove the zero:
d + -1pq + p2 = -1p

Add 'pq' to each side of the equation.
d + -1pq + pq + p2 = -1p + pq

Combine like terms: -1pq + pq = 0
d + 0 + p2 = -1p + pq
d + p2 = -1p + pq

Add '-1p2' to each side of the equation.
d + p2 + -1p2 = -1p + pq + -1p2

Combine like terms: p2 + -1p2 = 0
d + 0 = -1p + pq + -1p2
d = -1p + pq + -1p2

Simplifying
d = -1p + pq + -1p2

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