p+(2p+5)+-5(1+-2p)=2(3+4p)+-3(p+-4)

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Solution for p+(2p+5)+-5(1+-2p)=2(3+4p)+-3(p+-4) equation: 



p+(2p+5)+-5(1+-2p)=2(3+4p)+-3(p+-4)

We move all terms to the left:

p+(2p+5)+-5(1+-2p)-(2(3+4p)+-3(p+-4))=0

We add all the numbers together, and all the variables

p+(2p+5)-5(-2p)-(2(4p+3)+-3(p-4))+=0

We add all the numbers together, and all the variables

p+(2p+5)-5(-2p)-(2(4p+3)+-3(p-4))=0

We use the square of the difference formula

p+(2p+5)-5(-2p)-(2(4p+3)-3(p-4))=0

We multiply parentheses

p+(2p+5)+10p-(2(4p+3)-3(p-4))=0

We get rid of parentheses

p+2p+10p-(2(4p+3)-3(p-4))+5=0



We calculate terms in parentheses: -(2(4p+3)-3(p-4)), so:

2(4p+3)-3(p-4)

We multiply parentheses

8p-3p+6+12

We add all the numbers together, and all the variables

5p+18

Back to the equation:

-(5p+18)



We add all the numbers together, and all the variables

13p-(5p+18)+5=0

We get rid of parentheses

13p-5p-18+5=0

We add all the numbers together, and all the variables

8p-13=0

We move all terms containing p to the left, all other terms to the right

8p=13

p=13/8

p=1+5/8

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