p+-1(2p+5)+-5(1+-2p)=2(3+4p)+-3(p+-4)

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Solution for p+-1(2p+5)+-5(1+-2p)=2(3+4p)+-3(p+-4) equation: 



p+-1(2p+5)+-5(1+-2p)=2(3+4p)+-3(p+-4)

We move all terms to the left:

p+-1(2p+5)+-5(1+-2p)-(2(3+4p)+-3(p+-4))=0

We add all the numbers together, and all the variables

p-1(2p+5)-5(-2p)-(2(4p+3)+-3(p-4))++=0

We add all the numbers together, and all the variables

p-1(2p+5)-5(-2p)-(2(4p+3)+-3(p-4))=0

We use the square of the difference formula

p-1(2p+5)-5(-2p)-(2(4p+3)-3(p-4))=0

We multiply parentheses

p-1(2p+5)+10p-(2(4p+3)-3(p-4))=0



We calculate terms in parentheses: -(2(4p+3)-3(p-4)), so:

2(4p+3)-3(p-4)

We multiply parentheses

8p-3p+6+12

We add all the numbers together, and all the variables

5p+18

Back to the equation:

-(5p+18)



We add all the numbers together, and all the variables

11p-1(2p+5)-(5p+18)=0

We get rid of parentheses

11p-1(2p+5)-5p-18=0

We add all the numbers together, and all the variables

6p-1(2p+5)-18=0

We move all terms containing p to the left, all other terms to the right

6p-1(2p+5)=18

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