p+1=2(p-3)-3(p-1)

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Solution for p+1=2(p-3)-3(p-1) equation: 



p+1=2(p-3)-3(p-1)

We move all terms to the left:

p+1-(2(p-3)-3(p-1))=0



We calculate terms in parentheses: -(2(p-3)-3(p-1)), so:

2(p-3)-3(p-1)

We multiply parentheses

2p-3p-6+3

We add all the numbers together, and all the variables

-1p-3

Back to the equation:

-(-1p-3)



We get rid of parentheses

p+1p+3+1=0

We add all the numbers together, and all the variables

2p+4=0

We move all terms containing p to the left, all other terms to the right

2p=-4

p=-4/2

p=-2

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