p+2(p-4)=-3p+7(p+4)

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Solution for p+2(p-4)=-3p+7(p+4) equation: 



p+2(p-4)=-3p+7(p+4)

We move all terms to the left:

p+2(p-4)-(-3p+7(p+4))=0

We multiply parentheses

p+2p-(-3p+7(p+4))-8=0



We calculate terms in parentheses: -(-3p+7(p+4)), so:

-3p+7(p+4)

We multiply parentheses

-3p+7p+28

We add all the numbers together, and all the variables

4p+28

Back to the equation:

-(4p+28)



We add all the numbers together, and all the variables

3p-(4p+28)-8=0

We get rid of parentheses

3p-4p-28-8=0

We add all the numbers together, and all the variables

-1p-36=0

We move all terms containing p to the left, all other terms to the right

-p=36

p=36/-1

p=-36

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