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p-12=8-5(p-2)
We move all terms to the left:
p-12-(8-5(p-2))=0
We calculate terms in parentheses: -(8-5(p-2)), so:We get rid of parentheses
8-5(p-2)
determiningTheFunctionDomain -5(p-2)+8
We multiply parentheses
-5p+10+8
We add all the numbers together, and all the variables
-5p+18
Back to the equation:
-(-5p+18)
p+5p-18-12=0
We add all the numbers together, and all the variables
6p-30=0
We move all terms containing p to the left, all other terms to the right
6p=30
p=30/6
p=5
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