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p-3/4p=28
We move all terms to the left:
p-3/4p-(28)=0
Domain of the equation: 4p!=0We multiply all the terms by the denominator
p!=0/4
p!=0
p∈R
p*4p-28*4p-3=0
Wy multiply elements
4p^2-112p-3=0
a = 4; b = -112; c = -3;
Δ = b2-4ac
Δ = -1122-4·4·(-3)
Δ = 12592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12592}=\sqrt{16*787}=\sqrt{16}*\sqrt{787}=4\sqrt{787}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-4\sqrt{787}}{2*4}=\frac{112-4\sqrt{787}}{8} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+4\sqrt{787}}{2*4}=\frac{112+4\sqrt{787}}{8} $
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