p-30+2p-63=2(2p-78)

Solution for p-30+2p-63=2(2p-78) equation:

p-30+2p-63=2(2p-78)

We move all terms to the left:

p-30+2p-63-(2(2p-78))=0

We add all the numbers together, and all the variables

3p-(2(2p-78))-93=0


We calculate terms in parentheses: -(2(2p-78)), so:

2(2p-78)

We multiply parentheses

4p-156

Back to the equation:

-(4p-156)


We get rid of parentheses

3p-4p+156-93=0

We add all the numbers together, and all the variables

-1p+63=0

We move all terms containing p to the left, all other terms to the right

-p=-63

p=-63/-1

p=+63