p2+0.5p+0.625=1

Solution for p2+0.5p+0.625=1 equation:

p2+0.5p+0.625=1

We move all terms to the left:

p2+0.5p+0.625-(1)=0

We add all the numbers together, and all the variables

p^2+0.5p-0.375=0

a = 1; b = 0.5; c = -0.375;
Δ = b2-4ac
Δ = 0.52-4·1·(-0.375)
Δ = 1.75
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{1.75}}{2*1}=\frac{-0.5-\sqrt{1.75}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{1.75}}{2*1}=\frac{-0.5+\sqrt{1.75}}{2}
$