p2+300p-60000=0

Solution for p2+300p-60000=0 equation:

p2+300p-60000=0

We add all the numbers together, and all the variables

p^2+300p-60000=0

a = 1; b = 300; c = -60000;
Δ = b2-4ac
Δ = 3002-4·1·(-60000)
Δ = 330000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{330000}=\sqrt{10000*33}=\sqrt{10000}*\sqrt{33}=100\sqrt{33}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-100\sqrt{33}}{2*1}=\frac{-300-100\sqrt{33}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+100\sqrt{33}}{2*1}=\frac{-300+100\sqrt{33}}{2}
$