p2+32p+256=0

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Solution for p2+32p+256=0 equation: 



p2+32p+256=0

We add all the numbers together, and all the variables

p^2+32p+256=0

a = 1; b = 32; c = +256;
Δ = b2-4ac
Δ = 322-4·1·256
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{-32}{2}=-16$

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