p2+4p=11

Solution for p2+4p=11 equation:

p2+4p=11

We move all terms to the left:

p2+4p-(11)=0

We add all the numbers together, and all the variables

p^2+4p-11=0

a = 1; b = 4; c = -11;
Δ = b2-4ac
Δ = 42-4·1·(-11)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{15}}{2*1}=\frac{-4-2\sqrt{15}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{15}}{2*1}=\frac{-4+2\sqrt{15}}{2}
$