p2-12=11p

Solution for p2-12=11p equation:

p2-12=11p

We move all terms to the left:

p2-12-(11p)=0

We add all the numbers together, and all the variables

p^2-11p-12=0

a = 1; b = -11; c = -12;
Δ = b2-4ac
Δ = -112-4·1·(-12)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-13}{2*1}=\frac{-2}{2}
=-1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+13}{2*1}=\frac{24}{2}
=12
$