p2-16p+64=0

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Solution for p2-16p+64=0 equation: 



p2-16p+64=0

We add all the numbers together, and all the variables

p^2-16p+64=0

a = 1; b = -16; c = +64;
Δ = b2-4ac
Δ = -162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{16}{2}=8$

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