p2-7p+3=0

Solution for p2-7p+3=0 equation:

p2-7p+3=0

We add all the numbers together, and all the variables

p^2-7p+3=0

a = 1; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·1·3
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{37}}{2*1}=\frac{7-\sqrt{37}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{37}}{2*1}=\frac{7+\sqrt{37}}{2}
$