p2=315

Solution for p2=315 equation:

p2=315

We move all terms to the left:

p2-(315)=0

We add all the numbers together, and all the variables

p^2-315=0

a = 1; b = 0; c = -315;
Δ = b2-4ac
Δ = 02-4·1·(-315)
Δ = 1260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1260}=\sqrt{36*35}=\sqrt{36}*\sqrt{35}=6\sqrt{35}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{35}}{2*1}=\frac{0-6\sqrt{35}}{2}
=-\frac{6\sqrt{35}}{2}
=-3\sqrt{35}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{35}}{2*1}=\frac{0+6\sqrt{35}}{2}
=\frac{6\sqrt{35}}{2}
=3\sqrt{35}
$