p=(p+54)/10

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Solution for p=(p+54)/10 equation: 



p=(p+54)/10

We move all terms to the left:

p-((p+54)/10)=0

We multiply all the terms by the denominator


p*10)-((p+54)=0

Wy multiply elements

10p^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{20}=0$

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